WebAnswer. Both (a) and (b) Reason — The if condition checks that a and b are unequal and a and c are equal. Both these conditions should be true then only if statement will execute. If a and b are unequal and a and c are equal then b will either be the smallest number or the greatest number. Answered By. WebJun 1, 2015 · 4 Answers Sorted by: 3 Smallest is always initialized as 0 here: int smallest = numbers [0]. Unless the user enters a value smaller than 0, smallest value will stay 0. Use Integer.MAX_VALUE ( int smallest = Integer.MAX_VALUE) instead to ensure that the smallest number will actually be selected. Share Follow answered Jun 1, 2015 at 18:28 …
Find HCF of at most 3 numbers in Java - CodeSpeedy
WebJan 19, 2024 · public class LargestNestedIfDemo { public static void main (String [] args) { int num1 = 36, num2 = 35, num3 = 56; if (num1 >= num2) { if (num1 >= num3) { System. out .println (num1 + " is largest number."); } else { System. out .println (num3 + " is largest number."); } } else { if (num2 >= num3) { System. out .println (num2 + " is largest … WebHere we will write two java programs to find the largest among three numbers. 1) Using if-else..if 2) Using nested If To understand these programs you should have the knowledge of if..else-if statement in Java. If you are new to java start from Core Java tutorial. Example 1: Finding largest of three numbers using if-else..if pony express station in gothenburg nebraska
Java Program - Find Largest of Three Numbers - TutorialKart
WebEnter a,b,c: 3 5 8 c is Greater than a and b Explanation: Consider three numbers a=5,b=4,c=8 if (a>b && a>c) then a is greater than b and c now check this condition for the three numbers 5,4,8 i.e. if (5>4 && 5>8) /* 5>4 is true but 5>8 fails */ so the control shifts to else if condition else if (b>a && b>c) then b is greater than a and c WebJun 17, 2015 · import java.util.Scanner; public class LargestSmallestNum { public void findLargestSmallestNo () { int smallest = Integer.MAX_VALUE; int large = 0; int num; … WebSystem.out.println("result through naive method = "+ small); } } enter 1st number 25 enter 2nd number 10 enter 3rd number (if there is no 3rd number simply enter 0) 0 result through recursive method = 5 result through naive method = 5. Hope you understand the code to find HCF of at most 3 numbers in Java. shaper 3d cost